A man buys 12 lts of liquid which contain 20% of the liquid and the rest is water. he then mixes it with 10lts of another mixture with 30% of liquid. what is the % of water in the new mixture?
Answers
Answered by
5
12 litres contain 20% liquid and 80% water
12 litres== 2.4L liquid, 9.6 L water
10 litres of another liquid contain 30% liquid and 70% water
10 litres== 3 L liquid, 7 L water
Total mixture = 22 litres
Total water = 16.6 litres
% water in the new mixture = 16.6/22 * 100 = 75.45% (approx)
12 litres== 2.4L liquid, 9.6 L water
10 litres of another liquid contain 30% liquid and 70% water
10 litres== 3 L liquid, 7 L water
Total mixture = 22 litres
Total water = 16.6 litres
% water in the new mixture = 16.6/22 * 100 = 75.45% (approx)
Answered by
1
Answer:
fraction of 20%=1/5
30% =3/10
means , Water : Liquid Total
( 5 : 1 6) * 13
(10 : 3 13) * 6
--------------------------------------------------------
65 : 13 78
+ 60 : 18 78
--------------------------------------------------------
125 : 31
|_difference_ |
94
So now, (94/125)*100=75.2% Ans
Step-by-step explanation:
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