Question

A man buys 3 tables and 12 chairs for Rs. 2400. He sell the tables at a profit of 20% and the chairs at a profit of 10% and makes a total profit of Rs. 300. At what price did he buy the tables and chairs?

Answer 1

Answer:

Step-by-step explanation:

Let the price of 1 table be x

And, the price of 1 chair be y

Then, according to the question,

3x+12y = 2400

3(x+4y) = 2400

x+4y =2400/3

x+4y =800 -(1)

Now, profit of 3table=20% (given)

Then,3x×20/100=60x/100

And, profit of 12chair= 10% (given)

Then, 12y×10/100=120y/100

And, sum of both profits = 300

Then, 60x/100+120y/100=300

60x+120y = 300×100

60x+120y = 30000

60(x+2y) = 30000

x+2y = 30000/60

x+2y = 500 -(2)

NOW ,from equation 1 and 2, we get,

on substituting, we have

x+4y = 800

_x+2y =500

2y = 300

y = 300/2=150

Now put the value of y in equation -(1)

x+4y = 800

x+4(150)=800

x+600=800

x=800-600

x = 200

Hence the price of 1 table is 200

And the price of 1 chair is 150