Question

solve:2x^2-3x-2=0 linear equation

Answer 1

$2 {x}^{2} - 3x - 2 = 0 \\ = > 2 {x}^{2} - (4 - 1)x - 2 = 0 \\ = > 2 {x}^{2} - 4x + x - 2 = 0 \\ = > 2x(x - 2) + 1(x - 2) = 0 \\ = > (2x + 1)(x - 2) = 0$

Either;

$2x + 1 = 0 \\ = > 2x = - 1 \\ = > x = \frac{ - 1}{2}$

Or,

$x - 2 = 0 \\ = > x = 2$