Question

A man buys a 0lot of land for Rs 360000.he sells one-third of the plot at a loss of 20%.again he sells two-thirds of the plot left at a profit of 25%.At what price he sell the remaining plot in order to get a profit of 10% on the whole

Answer 1

First Method

CP = 3600000.

To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.

1/3 of the land sold on 20% loss.

SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.

SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.

Thus, SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.

Second Method

SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000.

So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.

SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.

Hence,

SP of the remaining field = Rs. (396000-96000-180000).

= Rs. 120000.