A man buys a plot of agriculture land for ₹ 360000. He sells one-third of it at a loss of 20% and two-fifth at a gain of 25%. At what price must he sell the remaining field so as to make an overall profit of 10%.
Answers
A man buys a field of agricultural land for Rs. 3,60,000. He sells one-third at a loss of 20% and two-fifths at a gain of 25%. At what price must he sell the remaining field so as to make an overall profit of 10%?
A. Rs.1,00,000
B. Rs. 1,15,000
C. Rs. 1,20,000
D. Rs. 1,25,000
Answer: Option C
Solution(By Examveda Team)
First Method
CP = 3600000.
To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.
1/3 of the land sold on 20% loss.
SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.
SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.
Thus, SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.
Second Method
SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000.
So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.
SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.
Hence,
SP of the remaining field = Rs. (396000-96000-180000).
= Rs. 120000.
Step-by-step explanation:
Answer is correct
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