The angle of elevation of the top B of a tower AB from a point X on the ground is 60 .at a point Y 40 m vertically above X the angle of elevation is 45 find the height of the tower AB and the distance AB
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AB = (20√3+60)m
AX = CY = (20√3+20)m
AX = CY = (20√3+20)m
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