Math, asked by gwagonte, 1 year ago

A man buys a plot of land at 3, 60, 000 .He sells one third of the plot at a loss of 20%. Again, he sells two third of the plot left at a profit of 25%. At what price should he sell the remaining plot in order to get a profit of 10% on the whole?

Answers

Answered by pravinsir
2
total cost of land is = 360000

so cost of 1/3rd plot = 360000/3 = 120000 rs

it's selling price is = 120000 × 80 /100

= 96000 rs

remaining plot is 2/3

2/3 of 2/3 = 4/9 th sells by 25 % profit

it's cost is = 360000×4/9

= 160000

so it's selling price is = 160000×125/100

= 200000 rs

now if you want 10% profit on 360000 rs


profit should be 36000

so selling price of whole land = 360000 + 36000

= 396000 rs


selling price till now , 96000 + 200000

296000 rs

so remained plot should sell at price 100000 rs

remaining plot is 2/9 th

it's cost is = 360000×2/9

= 80000


so 80000 rs plot sells at 100000 rs indicates 25% profit ...

pravinsir: Mark it as brainliest plz
gwagonte: I dont want ta mark you as brainliest but by mistake i marked uou as brainliest
gwagonte: and by the way the answer 150000
Answered by Deepsbhargav
2
cost \: price \: of \: land \: = \: 360000 \\ <br /><br />overall \: profit \: = \: 360000 \times \frac{10}{100} = \: 36000 \\<br /><br /> target \: sale \: value \: to \: achieve \: 10\% \: profit \: on \: the \: whole \: profit \: = \: 360000 + 36000 = 396000 \\ now \\  cost \: of \: \frac{1}{3} plot \: = \: 360000 \times \frac{1}{3} = \: 120000 \\ <br /> cost \: of \: \frac{2}{3} plot \: = \: 360000 \times \frac{2}{3} = \: 240000 \\  cost \: of \: \frac{2}{3} plot \: of \: \frac{2}{3} (plot \: left \: after \: selling \: \frac{1}{3} plot) = \: 240000 \times \frac{2}{3} = \: 160000 \\  20\% \: loss \: amount \: on \: sale \: of \frac{1}{3} plot \: = \: 120000 \times \frac{20 }{100} = \: 24000 \\  sale \: price \: of \: \frac{1}{3} part \: = a - 24000 \: = \: 96000(s _{1}) \\  remainig \: plot \: is \: \frac{2}{3} \\man \: sells \: \frac{2}{3} \: of \: this \: \frac{2}{3} plot \: at \: a \: profit \: of \: 25\% \: = \: 160000 \times \frac{25}{100} = \: 40000 \\  sale \: price \: of \: \frac{2}{3} \: of \: \frac{2}{3} plot \: = \: 160000 + 40000 = 200000(s _{2}) \\total \: sale \: value \: realized \: so \: far \: r \: = \: s _{1} + s _{2} \\=&gt; r \: = \: 96000 + 200000 \: = \: 296000 \\ target \: of \: sale \: value \: to \: achieve \: 10\% \: profit \: on \: the \: whole \: plot \: = \: s \\ required \: sale \: price \: for \: the \: remainig \: plot \: = \: s - r \: = \: 396000 - 296000 \: = \: 100000 \\ hope \: it \: wil \: help \: you \:

Devil_king ▄︻̷̿┻̿═━一

gwagonte: the answer is 150000
Deepsbhargav: ok
Deepsbhargav: sorry for wrong answer
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