A man buys a plot of land at 3, 60, 000 .He sells one third of the plot at a loss of 20%. Again, he sells two third of the plot left at a profit of 25%. At what price should he sell the remaining plot in order to get a profit of 10% on the whole?
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total cost of land is = 360000
so cost of 1/3rd plot = 360000/3 = 120000 rs
it's selling price is = 120000 × 80 /100
= 96000 rs
remaining plot is 2/3
2/3 of 2/3 = 4/9 th sells by 25 % profit
it's cost is = 360000×4/9
= 160000
so it's selling price is = 160000×125/100
= 200000 rs
now if you want 10% profit on 360000 rs
profit should be 36000
so selling price of whole land = 360000 + 36000
= 396000 rs
selling price till now , 96000 + 200000
296000 rs
so remained plot should sell at price 100000 rs
remaining plot is 2/9 th
it's cost is = 360000×2/9
= 80000
so 80000 rs plot sells at 100000 rs indicates 25% profit ...
so cost of 1/3rd plot = 360000/3 = 120000 rs
it's selling price is = 120000 × 80 /100
= 96000 rs
remaining plot is 2/3
2/3 of 2/3 = 4/9 th sells by 25 % profit
it's cost is = 360000×4/9
= 160000
so it's selling price is = 160000×125/100
= 200000 rs
now if you want 10% profit on 360000 rs
profit should be 36000
so selling price of whole land = 360000 + 36000
= 396000 rs
selling price till now , 96000 + 200000
296000 rs
so remained plot should sell at price 100000 rs
remaining plot is 2/9 th
it's cost is = 360000×2/9
= 80000
so 80000 rs plot sells at 100000 rs indicates 25% profit ...
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