A man buys a plot of land at rs 3,60,000.he sells one third of the plot at a loss of 20 percent again he sells two-thirds of the plot left at a profit of 25 percent.At what price should he sell the remaining plot in order to get a profit of 10 percent on the whole .
Answers
Cost = Rs 3, 60, 000.
cost of 1/3 of the plot = Rs 1,20,000.
loss due to its sale = 20% = Rs 24,000.
cost of the second 1/3 of the plot = Rs 1,20,000
Profit due to its sale = 25% = Rs 30,000.
Net profit to be gained on the overall sales = 10% = Rs 36, 000.
Profit to be gained from the sale of third part = Rs 36,000 - 30, 000 + 24,000
= Rs 30,000
So Sale price for the last 1/3 of the plot = Rs 1,20, 000 + Rs 30, 000
= Rs 1, 50, 000.
An
alternate approach:
CP = 3600000.
To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs.
396000.
1/3 of the land sold on 20% loss.
SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.
SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5
= Rs. 180000.
Thus, SP of the remaining land = 396000 - 96000 - 180000 =
Rs. 120000.
Or,
SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs.
396000.
So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.
SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.
Hence,
SP of the remaining field = Rs. (396000-96000-180000).
= Rs. 120000.
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