Question

a man can reduce his speed from 20kph to 18kph.so he takes 10mins more than normal time.what is distance covered?​

Answer 1

Answer:

I hope that this will help you

Step-by-step explanation:

Usual time = 9 × 10 = 90 min = 32

h

Thus,

Distance traveled = Speed × time = 20×32

= 30 km.

Alternatively,

As the speed decreases from 20 kmph to 18 kmph i.e. 10 % increment in usual time.

10% = 10 min

100% = 100 min.

Now,

Distance traveled by him,

= 10060×18

= 30 km.