Math, asked by divyasharan29005, 7 months ago

A man can row down the stream 20 km in 2 hrs and up the stream 4 km in 2 hrs. Find the spread of rowing in still water. And find the speed of current.​

Answers

Answered by SOUMYA2962
0

Answer:

Let, speed of man in still water be x km/hr

and speed of current be y km/hr

Then speed downstream =(x+y) km/hr

speed upstream =(x−y) km/hr

we know, Time=SpeedDistance

Then x+y20=2 and x−y4=2

⇒x+y=10 ...(1)

&   x−y=2 ...(2)

adding both we get, 2x=12⇒x=6

Thus using (1) y=10−6=4

Hence the speed of man in still water is 6 km/hr and the speed of the current is 4 km/hr.

Answered by medicalpandi
0

Answer:

ANSWER

Let, speed of Ritu in still water be x km/hr

and speed of current be y km/hr

Then speed downstream =(x+y) km/hr

speed upstream =(x−y) km/hr

we know, Time=

Speed

Distance

Then

x+y

20

=2 and

x−y

4

=2

I hope it's help u

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⇒x+y=10 ...(1)

& x−y=2 ...(2)

adding both we get, 2x=12⇒x=6

Thus using (1) y=10−6=4

Hence the speed of Ritu in still water is 6 km/hr and the speed of the current is 4 km/hr.

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