A man can swim 48m/min in still water he swims 200m against the current and 200m with the current. if the difference
Answers
Answered by
18
The question is incomplete. Here is the complete question:
A man who can swim 48 m/min in still water swims 200 m against the current and 200 m with the current. If the difference between those 2 times is 10 minutes, find the speed of the current.
A) 30 m/min
B) 29 m/min
C) 31 m/min
D) 32 m/min
Answer:
Option D is the answer
(200/(48 - 32)) - (200/ (48 + 32)) (12(1/2)min - 2(1/2)min)
= 10 min
If there is any confusion please leave a comment below.
Answered by
0
Answer:
32
Step-by-step explanation:
It's difficult to solve in direct way.... So try to solve it by subst answers!
U=48
V=?
The diff of two ups and downs (time) have to came 10
200/(48-32)-200(48+32)=10//
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