Question

A man can throw a ball to a maximum horizontal distance of 100 m.
then what would be maximum vertical distance upto which he can
throw the ball assuming the ball to have same initial velocity.
Ans. 50 metre​

Answer 1

We know that maximum horizontal range is,

R = u² / g.

Given,

R = u² / g = 100 m.

We know the maximum height of a projectile,

u² sin²θ / 2g.

Maximum height is obtained when θ = 90°, i.e., when the body is projected vertically upwards.

So, maximum height is,

H = u² / 2g = (u² / g) / 2 = R / 2

That's why the answer is H = 100 / 2 = 50 m.

Answer 2

Rmax = u^2÷g = 100

Hmax = u^2÷2g =100÷2 =50metrr