A man covers a distance on scooter. Had he moved 3kmph faster he would have taken 40 min less. If he had moved 2kmph slower, he would have taken 40min more. The distance is.
A. 30 km
B. 40 km
C. 45 km
D. 50 km
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Let distance=x m
Usual rate =y kmph
X/y-x/y+3=40/60
2y(y+3)=9x--------1
X/y-2-x/y=40/60hours y(y-2)=3x-–--------2
By solving this equation we get 40
Usual rate =y kmph
X/y-x/y+3=40/60
2y(y+3)=9x--------1
X/y-2-x/y=40/60hours y(y-2)=3x-–--------2
By solving this equation we get 40
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