If θ and 3θ-30° are acute angles such that sinθ=cos(3θ-30°),then find the value of tanθ.
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Given
Sin @= cos (3@-30)
Or cos (90-@) = cos (3@-30)
Or 90-@=3@-30
Or
90+30=3@+@
Or
120=4@
Or @=30
Now
Tan @=tan 30 = 1/ root 3
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