A man covers distance in 7 hours he coverd one third at 45kmph and remaining 36 kmph the distance coverd by man is?
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Heya
Let the distance covered by the man be y
According to the question,
He covered y/3 distance at 45kmph.
Speed=distance/time
Time = distance /speed
T1 = y/3/45
T1 = y/135
He covered remaining 2y/3 at a speed of 36kmph
T2 = 2y/3/36
T2 = y/54
T1+T2=7
y/135 +y/54 = 7
(2y+5y) / 270 = 7
7y/270 = 7
y= 7×270/7
y = 270km
Hope it helps^_^
Let the distance covered by the man be y
According to the question,
He covered y/3 distance at 45kmph.
Speed=distance/time
Time = distance /speed
T1 = y/3/45
T1 = y/135
He covered remaining 2y/3 at a speed of 36kmph
T2 = 2y/3/36
T2 = y/54
T1+T2=7
y/135 +y/54 = 7
(2y+5y) / 270 = 7
7y/270 = 7
y= 7×270/7
y = 270km
Hope it helps^_^
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