Question

A man covers distance of 14 km in an hour.partly on foot at4 km per hrs and on scooter at 44 km per hrs. Find distance travelled by him on foot?

Answer 1

Let distance covered on foot be x kms and that by scooter be (14-x) kms. Let the time taken to cover x kms on foot be t hrs, and that to cover (14-x) kms on scooter be (1-t) hrs.
Speed = Distance covered/time taken to cover the distance ⇒ distance covered = speed×time required to cover that distance.
x = 4×t ......................... equation 1
14-x = 44(1-t)............... equation 2
Substituting x = 4t in equation 2, we get
14-4t = 44-44t ⇒ 40t = 30 ⇒ t = 3/4 hours.
Distance covered on foot = speed×time required to cover the distance = 3/4×4 = 3 kms.

Answer 2

Hello Dear.

Here is the answer---

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Let the Distance covered by the man by foot be x km.
∴ Distance by Scooter = (14 - x)

For Foot.
Speed = 4 km/hr.
Distance = x km.

Using the Formula,

  Speed = Distance/Time
 Time(T₁) = x/4

For Scooter.
Distance = (14 - x)km.
Speed = 44 km/hr.

∴ Time(T₂) = (14 - x)/44


As per as the Question,

 T₁ + T₂ = 1
$\frac{x}{4} + \frac{14 - x}{44}$ = 1
$\frac{11x + 14 - x}{44}$ = 1
 10x + 14 = 44
  10x = 44 - 14
  10x = 30
    x = 3

∴ Distance covered by the man from the Foot = x
 = 3 hours.

∴ Distance covered by the man from Scooter = (14 - x) km.
 = 14 - 3
 = 11 km.


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Hope it helps.