Question

A man covers his body with a blanket of thickness 4 mm. His temperature is 37°C and that of the

atmosphere is 27°C. If the coefficient of thermal conductivity of wool is 1.2×10^-5 MKS units, heat lost by

him per hour per square meter area is​

Answer 1

Answer:

Step-by-step explanation:

→ It is given here,

K = 1.2 x 10^(-5) W/mk

T1 – T2 = 10 K

d = 4 x 10^(-3)  

→ Heat conduction:

d Q / d t = κ A ( T 1 − T 2 ) / d  

where,

dQ/dt = the rate of heat transfer through the conducting material.  

1 / A*  ( d Q / d t ) = κ ( T 1 − T 2 )/ d  

Joules/m^2hour = (Joules x 3600)/m^2(3600 sec)

=  [1.2 x 10^(-5) x 10 x 3600]/(4 x 10^(-3))

= 108 Joules/m^2

Thus, heat lost by him per hour per square meter area is​ 108 Joules/m^2