Question

a man cycles to his office from his house at a speed 5 km/ hour and reaches 10 minutes late. if he cycles at a speed of 6 km/hour, he reaches 10 minutes early. what is the distance between the office and his house ?

Answer 1

Hey mate..... Here is your answer:

Let d = the distance in km between house and office

Let t = The travel time in hrs which is on time for him

Given:

From office to house at 5 km/hr
(1) d=5×(t+10/60)

From office to house at 6 km/hr
(2) d=6×(t-10/60)
--------------------—-------------------------

(1)d=5t+5/6
(2)d=6t-1

-------------------—---------------------------

Substitute (1) into (2)

(2) 5t+5/6=6t-1
t=5/6+1
t=11/6

Plug this result back into (1) or (2)

(1) d=5×(11/6)+5/6
d=55/6+5/6
d=10

The distance between his house and office is 10 km
check:

(2) d=6t-1
(2) 10=6t-1
(2)6t=11
(2)t=11/6

OK

(1) d=5t+5/6
(1) 10=5t+5/6
(1) 5t=10-5/6
(1)5t=60/6-5/6
(1)5t=55/6
(1)t=11/6

Ok!!!

#Be Brainly✌️

Answer 2

Answer:

10km bro

Step-by-step explanation:

**** bro , it's good morning