Question

A man decided to donate 60000 collected from his three sons to prime minster relief fund the elder son contributed 3/8 of his youngest brothers contribution while second son contributed 1/2 of his youngest brother share find the contribution of all

Answer 1

Let contribution of 3rd brother = x
Therefore, contribution of 1st brother = 3x/8
And contribution of 2nd brother =1x/2
ATQ :
x + 3x/8 + 1x/2 = 60000
(8x + 3x + 4x)/8 = 60000
15x = 60000 × 8
15x = 480000
x = 480000/15
= 32000
So, contribution of 3rd brother = x
= 32000
Contribution of 1st brother =
(3 × 32000)/8 = 12000
Contribution of 2nd brother =
(1 × 32000)/2 = 16000

Answer 2

Answer:

third brother let x

1st brother 3x/8

2nd brother x/2

so

x+3x/8+x2=60000

(8x+3x4x)/8=60000

8x+3x+4x=60000*8

8x+3x+4x=480000

15x=480000

x=480000/15

x=32000

so, 1st

brother 3x*32000/8=12000

2nd brother 1*32000/2

=16000