Question

A man deposited 590 rupees cheque in a bank.The bank gave him 5 rupees note and 10 rupees note of a total 70 notes.let us calculate by simulation equation that how many 5 rupees and 10 rupees note the bank gave​

Answer 1

Let the 5 rupee notes be x and 10 rupee notes be y respectively.

Acc. to question,

x+y=70 or x=70-y .........(i)

also, 5x+10y=590 .........(ii)

Therefore 5(70-y)+10y=590

350-5y+10y=590

5y=240

y=48

putting value of y in (i)

x=70-48=22

Therefore bank gave 22 five rupee notes and 48 ten rupee notes

Answer 2

The bank gave him 22 five rupees notes and 48 ten rupees notes

Solution:

Let the number of 5 rupees notes be "x"

Let the number of 10 rupees notes be "y"

The bank gave him 5 rupees note and 10 rupees note of a total 70 notes

Therefore,

x + y = 70 ------ eqn 1

A man deposited 590 rupees cheque in a ban

Therefore,

5x + 10y = 590 ----- eqn 2

calculate by substitution method

From eqn 1,

x = 70 - y ----- eqn 3

Substitute eqn 3 in eqn 2

5(70 - y) + 10y = 590

350 - 5y + 10 y = 590

5y = 590 - 350

5y = 240

y = 48

Substitute y = 48 in eqn 3

x = 70 - 48

x = 22

Thus the bank gave him 22 , 5 rupees notes and 48 , 10 rupees notes

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