a man devided his property among his three sons in the following manner : He gave Rs. 2,500 to the eldest, 5/12 of the whole property to the second and to the youngest as much as to the first and the second together. how much did the youngest get?
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Answer:
let total property be of rs. x
1st son = rs. 2500
2nd son = 5/12 * x
3rd son = rs. 2500 + 5/12 x
2500 + 5/12x + 2500 + 5/12x = x
5000 + 5/6 x =x
x-5/6x = 2500
(6x -5x) = 2500 * 6
x = 15000
3rd ( youngest son got ) = 2500 + 5/12 * 15000
= 2500 + 6250
= Rs. 8750
Step-by-step explanation:
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