Question

A man distributed a sum of 5,40,000 among his
four daughters such that six times the share of the
first daughter, four times the share of the second
daughter, thrice the share of the third daughter and
twice the share of the fourth daughter are all equal.
Find the share of each daughter.​

Answer 1

Answer

The shares of all four daughters will be

rs 2,16,000 ; 1,14,000; 1,08,000 and 72 , 000

Solution

Let the shares of daughters as

6x , 4x ,3x and 2x

we are given that total sum of money is rs 540000 , So

6x +4x+3x+2x = 540000

15 X = 540000

x. = 540000/15

x. = 36000

Now putting the value of X in share of each daughter .

6x = 6 × 36000

216000

4x = 4× 36000

114000

3x = 3× 36000

108000

2x = 2× 36000

72000

hope it helps