Math, asked by leenabhalla, 2 months ago

A man distributed his property among his three sons. He gave 2/7 part to his first son and 3/10 part to his second son. How much property did the third one get ?​

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

Let the whole property of a man be 1

Part of the Property given to his first son = \frac{2}{7}

Part of the Property given to his second son = \frac{3}{10}

So, left over property given to his third son = 1 - (\frac{2}{7} + \frac{3}{10})

                                                              = 1 -  \frac{41}{70} =  \frac{29}{70}

Answer is 29/70.

Thanks for this question.

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