Question

a man divides sum of money in three child such that the eldest child gets one more rupee than half the sum.the second child receive half the remainder while the third child recieves 600.find how much is recieved by eldest and second son​

Answer 1

M/3+(2/3)*(2M/3)+12 = M

3M/9+4M/9=9M/9–12 => -2M/9=-12 => 2M=9*12 => M= 54

54.

Check:

1st child gets 18 (36 is left)

2nd child gets 24

3rd child gets 12