Question

A man does a work of 800j while lifting a bucket of 40 kg from a well. Calculate the depth of well.(g=10m/S2)

Answer 1

Answer :-

• The depth of the well is 2 m.

To find :-

• The depth of the well.

Step-by-step explanation :-

• In this question, it is given that the work done by a man = 800J and the mass of the bucket is 40 kg. We have to calculate the depth of the well.

We know that :-

$\dashrightarrow\underline{\boxed{\textsf{Potential Energy = Workdone}}}$

$\dashrightarrow\underline{\boxed{\textsf{Potential Energy = mgh}}}$

Here,

• m = 40 kg
• g = 10 m/s²
• Potential energy = 800J

Let :-

• The depth of the well be "h" m.

Therefore,

$\longmapsto \sf{800 = 40 \times 10 \times h}$

$\longmapsto \sf{800 = 400 \times h}$

$\longmapsto \sf{800 = 400h}$

$\longmapsto \sf{\cancel{\dfrac{800}{400}} = h}$

$\longmapsto \sf{2 \: m = h}$

Hence,

• The depth of the well is 2 m.

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Answer 2

Answer:

2m

Explanation:

given,

work done=800J

mass of the bucket=40kg

g=10ms^-2

now,

w=F.S(w=workdone,F=force,s=displacement)

w=ma.s(F=ma)

800=40(10).h

800=400.h

h=800÷400

h=2m