Question

A man donated 1/10 of his money to a school, 1/6 of the remaining to a church and the remaining money he distributed equally among his three children .if each child gets 50000, how much money did the man originally have

Answer 1

Let man has money = P
A/C to question,

he donates P/10 amount to school
after donating rest amount = P - P/10 = 9P/10

again,
he donates 1/6 of 9P/10 to church = 9P/60

now , rest amount = 9P/10 - 9P/60 = 45P/60 = 3P/4

now , remaining amount he distributes his three children in equal amount .
e.g each child got money = P/4

but each child got money =50000
So, P/4 = 50000
P = 200000
hence, man has 200, 000 or 2 Lacks
amount

Answer 2

Let the money the man originally have be x

He donates 1/10 to a school
1/10 × x = x/10

Remaining money = x - x/10
= 9x/10

He donates 1/6 to a church from the remaining money,
1/6 × 9x/10 = 3x/20

Remaining money = 9x/10 - 3x/20
= 12x/20
= 3x/4

the remaining money he distributed equally among his three children
= 3(x/4)

So,each child gets x/4 amount.

According to the question,
If each child gets 50000 ,

x/4 = 50000
x = 200000

So the amount of money which the man originally have is 2,00,000.

Hope it helps