Question

a man drives his car 5km east of his starting point. then he travels 10 km south and reaches a point . from here travels 20 km towards north. find the net displacement of the man from where he started​

Answer 1

Answer:

5 km east

20km north -10 km south = 10 km north

disp =

$\sqrt{ {10}^{2} + {5}^{2} } = \sqrt{125}$

= 11.1 km approx