Question

A man drives his car with uniform speed from place a to the place B which is 150 kilometres away he returns to the place a by increasing the speed of the car 10 km per hour and there be reaches 30 minutes earlier than the time taken in his forward journey find the total time taken by him in forward and return journey

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

The total time required in the entire journey is 5.5 hours.

Step-by-step explanation:

Distance= 150km

Let the original speed be S, so the new speed is S+10

Original time = 150/S

New time = 150/( S+10)

Difference between both the time taken= 30 minutes or 1/2 hours.

So, according to the given conditions, we can form the equation as:

150/S - 150/( S+10) = 1/2

So, by solving this we get the equation:

S2+ 10S- 3000= 0

So, on solving it, we get S as 50

Original speed is 50km/hour , so new speed is 60 km/hour

So, original time is 150/50 = 3hours

New time is 150/60 = 2.5 hours

So, total time taken = 5.5 hours.