Question

A man drives his car with uniform speed from place A to the place B which is 150km away.again more than the distance between the point B and P. If the distance between point A and B is 10m and AB is longest side of the triangle ABC . Is ABC a right angled triangle or not, justify your answer using the discriminant of quadratic equation and also find the measure of AP and BP.​

Answer 1

Answer:

$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$

The total time required in the entire journey is 5.5 hours.

Step-by-step explanation:

Distance= $\huge{\fbox{\mathfrak{\black{150km}}}}$

Let the original speed be S, so the new speed is S+10

Original time = 150/S

New time = 150/( S+10)

Difference between both the time taken= 30 minutes or 1/2 hours.

So, according to the given conditions, we can form the equation as:

150/S - 150/( S+10) = 1/2

So, by solving this we get the equation:

S2+ 10S- 3000= 0

So, on solving it, we get S as 50

Original speed is 50km/hour , so new speed is 60 km/hour

So, original time is 150/50 = 3hours

New time is 150/60 = 2.5 hours

So, total time taken = 5.5 hours.

$<marquee>★᭄ꦿ᭄ꦿFOLLOW ME★᭄ꦿ᭄ꦿ<marquee>$

Answer 2

Answer:

$$\huge{\fbox{\fbox{\bigstar{\mathfrak{\red{Answer}}}}}}$$

The total time required in the entire journey is 5.5 hours.

Step-by-step explanation:

Distance= $$\huge{\fbox{\mathfrak{\black{150km}}}}$$

Let the original speed be S, so the new speed is S+10

Original time = 150/S

New time = 150/( S+10)

Difference between both the time taken= 30 minutes or 1/2 hours.

So, according to the given conditions, we can form the equation as:

150/S - 150/( S+10) = 1/2

So, by solving this we get the equation:

S2+ 10S- 3000= 0

So, on solving it, we get S as 50

Original speed is 50km/hour , so new speed is 60 km/hour

So, original time is 150/50 = 3hours

New time is 150/60 = 2.5 hours

So, total time taken = 5.5 hours.

Please mark my answer as brainliest and follow !!!!!!!