Question

a man driving at2/3 of his original speed reaches his destination

Answer 1

Heya user !!

Here's the answer you are looking for

Let the original velocity be v m/min and the original time be t min.

So, the distance it travels is (vt) metres.

If it travels at 2/3 of its original velocity then it takes 30 mins more.

But in both the cases it travels the same distance.

$so \\ vt = \frac{2v}{3} (t + 30) \\ vt = \frac{2vt}{3} + 20v \\ vt - \frac{2vt}{3} = 20v \\ \frac{vt}{3} = 20v \\ \\ cancel \: v \: from \: both \: sides \\ \\ \frac{t}{3} = 20 \\ \\ t = 20 \times 3 = 60min$


★★ HOPE THAT HELPS ☺️ ★★