Question

a man driving his moped at 24kmph reaches his destination 5 minutes late to an appointment. if he had driven at 30kmph he would have reached his destination 4 minutes before time.how far is his destination?

Answer 1

I hope this will help you

Answer 2

Hey mate!!!

$<b >Here is your answer ;</b >$

Let the time taken to reach the destination be $<b >x </b >$ min.

Speed1 is 24 km/h
Time more taken, t1 = 5.

Then, distance is speed * time

= $\frac{24 * (x + 5)}{60}$

= $\frac{2 * (x + 5)}{5}$ _eq1


Also,
Speed2 is 30km/h
Time less taken, t2 = 4.

Then, distance is speed * time

= $\frac{30 * (x - 4)}{60}$

= $\frac{1 * (x - 4)}{2}$ _eq2

By comparing eq1 and eq2.

We get,


$\frac{2 * (x + 5)}{5} = \frac{1 * (x - 4)}{2}$

==>>$4(x + 5) = 5(x - 4)$

==>>$4x + 20 = 5x - 20$

==>>$x = 40 mins.$


Now placing $x$ in eq2, we can get the distance as;

$\frac{(x - 4)}{2}$

=$\frac{(40 - 4)}{2}$

=$\frac{(36)}{2}$

= 18 km.



$<b ><big ><marquee >I hope it helps you #need more brainliests marks$