A man drops a 10 kg rock from the top of a 5 m ladder .what is its speed just before it hits the ground?
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Answer:
the velocity before hitting the ground = 10 m/s
PLEASE MARK IT AS A BRAINLIEST ANSWER
Explanation:
2as=v^2 - u^2
2×10×5=v^2
v=10 m/s
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