Question

Answer the question fast please along with the procedure

Answer 1

Answer:

2x³-5x²-14x+8

trial n error method

x= -2

we get 0, so one factor is (x+2)

2x³+4x²-9x²-18x+4x+8=0

2x²(x+2) -9x(x+2) +4(x+2) = 0

(x + 2)(2x² -9x +4) = 0

(x + 2)(2x² -8x - x + 4) = 0

(x + 2){2x(x-4) -1(x-4)} = 0

(x+2)(x-4)(2x-1) = 0

x = -2, 4, 1/2

sum of zeroes= -2+4+1/2= 2+1/2= 4+1/2= 5/2

product of zeroes= -2*4*1/2= -1*4= -4

sum of product of zeroes taken 2 at a time= -2(4)+4(1/2)+1/2(-2)

                                                                        = -8+2-1= -9+2

                                                                        = -7

proved

Step-by-step explanation: