A man drops a 10kg rock from the top of a 20m ladder. What will be its kinetic energy when it reaches the ground? What will be its speed just before it hits the ground? ( take g = 10m/s2
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M=10 kg
U= 0 m/sec
S=20m
a=g=10
KE =1/2 mv^2
V^2-U^2=2aS
V^2=(2×10×20 )+0
V^2=400
.KE=1/2MV^2
= 1/2 ×10×400
=2000J
U= 0 m/sec
S=20m
a=g=10
KE =1/2 mv^2
V^2-U^2=2aS
V^2=(2×10×20 )+0
V^2=400
.KE=1/2MV^2
= 1/2 ×10×400
=2000J
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