Question

A man earns ₹600.per month more than his wife one tenth of the men salary and one -sixth of the wife salary amount to ₹1500.which is saved every month find there incomes ​

Answer 1

Answer:

Man's income is ₹6000 and his wife's income is ₹5400.

Explanation:

Let the man's income be x

N his wife's income be y

So, ATQ,

x = 600+ y (1)

and, 1/10*x + 1/6*y= 1500

or x/10 + y/6 = 1500 (2)

Now putting value of eq. (1) in eq.(2), we get

600+y/10 + y/6 = 1500

taking LCM,

(3600+6y+10y)/60 = 1500

16y = (1500*60) - 3600

16y = 90000 - 3600

16y = 86400

y = 86400/16

y= 5400

therefore, y= ₹5400 and x = 600+ y

or x = 600+5400 = ₹6000

Answer 2

Answer:

Monthly income of wife = Rs. 5400

And, Monthly income of man = 5400+600 = Rs. 6000

Explanation:

Given,

A man earns ₹600.per month more than his wife one tenth of the men salary and one -sixth of the wife salary amount to ₹1500.

To find: Income of man and wife saved every month.

Concept Involved: Through the use of question's language we will form equations and solving those equations will get us the resultant.

Solution:

Let the monthly income of wife be x.

then, monthly income of man will be (x + 600)

Now, According to question,

1 (x + 600) / 10 + 1(x) / 6 = 1500

or, [ 3(x+600) + 5x] / 30 = 1500

or,  8x + 1800 = 1500 * 30

or, 8x = 45000 - 1800

or, x = 43200/8

or, x = 5400.

Therefore, Monthly income of wife = Rs. 5400

And, Monthly income of man = 5400+600 = Rs. 6000