Question

a man earns 600 per month more than hus wifr . one tenth of the mans salary and one sixth of his wifes salary amount to rs 1500,which is saved every month . find their incomes

Answer 1

Let salary of wife be x.
Thus, salary of man = x+600.

According to question,

(x+600/10) + (x/6) = 1500

(3*(x+600)/10*3) + (5*x/6*5) = 1500

(3x+1800/30) + (5x/30) = 1500

3x + 1800 + 5x = 1500*30

8x + 1800 = 45000

8x = 45000 - 1800

8x = 43200

x = 43200/8

x = 5400

Thus, salary of wife = 5400 and salary of man = 5400 + 600 = 6000.

Answer 2

$\huge \underline \bold \color{orchid} \mathcal{HEYA }$

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