Question

A MAn first movies 3m due east then6m north and finally 7m due west then the magnitude of the resultant displacement is in m

Answer 1

magnitude of displacement is root 52

Answer 2

Therefore the magnitude of the resultant displacement is 2√13 m.

Given : A man first moves 3m due east then 6m north and finally 7m due west.

To find : The magnitude of resultant is in metre.

Solution : step 1 : A man first moves 3m due east.

so, vector form of displacement, s₁ = 3i

step 2 : then he moves 6 north.

so, vector form of this displacement, s₂ = 6j

step 3 : and finally he moves 7 m due west.

so, vector form of 3rd displacement, s₃ = -7i

resultant displacement, s = s₁ + s₂ + s₃

= 3i + 6j - 7i

= 6j - 4i

= -4i + 6j

so, the magnitude of resultant displacement , |s| = √{(-4)² + (6)²} = √(16 + 36) = 2√13 m

Therefore the magnitude of the resultant displacement is 2√13 m.