A man gave 25% of the amount of money with him to his eldest son, 20% to his younger son, 20%
of the remainder to his daughter, and the rest Rs. 660 to his wife. Find the amount of money he
had with him.
a) Rs. 1550
b) Rs. 1560
c) Rs. 1500
d) Rs. 1540
Answers
Answer:
Let the man had Rs.x
Eldest son = 0.25x
Younger son = 0.2x
Remainder = 0.55x
Daughter =0.2×0.55x
Wife = 0.8×0.55x
800=0.8×0.55x
x=Rs. 1818.18
Ratio
0.25x:0.2x:0.11x
25:20:11
Step-by-step explanation:
Answer:
Let the amount of money he had be Rs. x.
Amount of money he gave to his eldest son=25% of Rs. x=Rs. (x/4)
Amount of money he gave to his younger son=20% of Rs. x=Rs. (x/5)
Amount of money left=Rs.{x-(x/4)-(x/5)}=Rs.(11/20)x
Amount of money he gave to his daughter =20% of Rs. (11/20)x=Rs. (11x/100)
Amount of money left=Rs.(11x/20)-Rs. (11x/100)=Rs. (11x/25)
Amount of money left was given by him to his wife=Rs. 880
=>11x/25=880
=>x=2000
:. He originally had Rs.2000.
Now, amount of money received by his eldest son=Rs(x/4) =Rs. 500
amount of money received by his younger son=Rs(x/5) =Rs. 400
Amount of money he gave to his daughter =Rs. (11x/100)=Rs. 220
:. Ratio of the money received by his eldest son, younger son and daughter=500:400:220=25:20:11