Question

A man goes 10 m due east and then 24 m due north. Find the distance from the starting point.

Answer 1

Answer:

26 meters

Step-by-step explanation:

We have,

Towards East = 10 m

Towards North = 24 m

Using Pythagoras Theorem,

$(Hypotenuse) {}^{2} = \\ (base) {}^{2} + (height) {}^{2} \\ = (10) {}^{2} + (24) {}^{2} \\ = 100 + 576 \\ = 676 \\ = (26) {}^{2}$

$starting \: point = \\ \sqrt{(Hypostenuse) {}^{2} } \\ \sqrt{( 26) {}^{2} } \\ 26$

Hence 26 Meters is the answer.

Hope this helps you✌✌