Question

. Sum of the digits of a two-digit number is 11. The given number is less

than the number obtained by interchanging the digits by 9. Find the number.​

Answer 1

Answer:

The given number is less than the number obtained by interchanging the digits by 9. Therefore, (10x+y)−(10y+x)=9. Putting the value of x in x+y=11, we get y=11−x=11−6=5. The number was 56.

Answer 2

Explanation:

. Sum of the digits of a two-digit number is 11. The given number is less

than the number obtained by interchanging the digits by 9. Find the number.