A man goes 10m sue east and then 24m north. Find hi distance from the starting point.
Options:
A) 26m
B)25m
C) 24m
D) 27m
Plz solve the question then write the option
Answers
Answered by
1
Hi,
Man goes towards east= 10m
Then he goes towards north = 24m
He makes a triangle |
|___
To get the total distance we need to find the 3rd side of triangle that is hypotenuse side.
Base = 10m
Height = 24m
hypotenuse side = (10)^2 ± (24)^2 (as the formula of hypotenuse is base square plus height square is equals to hypo...square(
(hypotenuse)^2 = 100±576
(Hypotenuse)^2 = 676
hypotenuse = 26 (square root of 676)
Answer is 26m!
I hope it will help you
Man goes towards east= 10m
Then he goes towards north = 24m
He makes a triangle |
|___
To get the total distance we need to find the 3rd side of triangle that is hypotenuse side.
Base = 10m
Height = 24m
hypotenuse side = (10)^2 ± (24)^2 (as the formula of hypotenuse is base square plus height square is equals to hypo...square(
(hypotenuse)^2 = 100±576
(Hypotenuse)^2 = 676
hypotenuse = 26 (square root of 676)
Answer is 26m!
I hope it will help you
Answered by
1
Option A is correct 26m.
He goes east 10m and then turn to north andd moves 24m
To find distance between his initial and final points we will find the distance between point A and point B (as show in the diagram) which equals AC.
Using pythagoras theorem:
(AC)^2 = 10^2 + 24^2
(AC)^3 = 100 + 576
AC = 26
So, the distance between hiis initial point would be 26m.
He goes east 10m and then turn to north andd moves 24m
To find distance between his initial and final points we will find the distance between point A and point B (as show in the diagram) which equals AC.
Using pythagoras theorem:
(AC)^2 = 10^2 + 24^2
(AC)^3 = 100 + 576
AC = 26
So, the distance between hiis initial point would be 26m.
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