Question

A man goes 12 m due west and then 5 m due north. How far is he from the starting point?
1 point
7 m
17 m
13 m
10 m​

Answer 1

Answer:

answer is 13 m....... ...........................

Answer 2

Solution :-

from image let the man starts from point A and goes to point B in west covering a distance of 12 m.

So,

→ AB = 12 m

now, from B he goes to point C in north covering a distance of 5 m.

So,

→ BC = 5 m

then, in right angled ∆ABC we have,

→ AC = √(AB² + BC²) { By pythagoras theorem }

→ AC = √(12² + 5²)

→ AC = √(144 + 25)

→ AC = √(169)

→ AC = 13 m (Ans.)

Hence, the man is 13 m far from the starting point .

Learn more :-

In the figure ∠ MNP = 90°, ∠ MQN = 90°, , MQ = 12 , QP = 3 then find NQ .

https://brainly.in/question/47411321

show that AB2 = AD.AC

https://brainly.in/question/47273910