Question

In a triangle ABC angle B=90°,Evaluate sin A cos C +cos A sin C​

Answer 1

Answer:

Given in △ ABC, ∠B=90°

.

This given A+C=180°−90° =90 ......(1).

Now,

sinA.cosC+cosA.sinC

=sin(A+C)

=sin(90° )

=1.

Answer 2

Answer:

1

Step-by-step explanation:

IN THE GIVEN TRIANGLE ABC, angleB = 90°

THIS given A + C = 180° - 90° = 90°.....(1)

Now,

sinA cosC + cosA sinC = sin( A + C)

= sin( 90°) = 1

THEREFORE THE CORRECT ANSWER IS 1.

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