Question

A man goes 12 m due West and then 5m due north. How far is he away from his starting position? 18 13 24 28​

Answer 1

Answer:

Total displacement = 12i + 5j

Therefore, total displacement = (12² + 5²) ^½

Therefore, D = √(144 + 25) = 13 m

Answer 2

Answer:

The man 13 meters away from his starting position.

Step-by-step explanation:

• 1st step - man goes firstly 12 meters west
• 2nd step - then man goes 5 meters north
• 3rd step - now we have to find how far is he away from his starting position
  Now, we will apply here Pythagoras theorem,
  "The sum of the squares of the 2 sides of the triangle ( base and perpendicular ) is equal to the square of Hypotenuse of that triangle."  
• H² = P² + B²
  Now, we have to put the value of the question
  B = 5m (distance from starting point to north)
  P = 12m (distance from 5m west to 12m north)
  Now, H² = 12² + 5²
           H² = 144+ 25
           H² = 169
           H = 13
  The man away 13 meters from his starting position
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