a man goes 24 m due west and then 10 m due north how far is he come from the starting point
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Answer:
26 m
Step-by-step explanation:
We can solve this by pythagoras theorem.
Let ABC be a triangle.
AB = West = 24 cm BC = North = 10 cm
AC² = AB²+ BC²
= 24² + 10² = 676
AC = 26 M
∴ The distance he is from starting point is 26 m
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