Question

a man goes 24 meter towards east and then 10 meter towards north hoe far is he away from initial position​

Answer 1

Answer:

a man goes to East=24m

and to North =10m

distance=(24)m2+10m2

576m2+100m2=676m2

root of 676m2=26m

hence he is 26 metre far away from his essential position

Step-by-step explanation:

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Answer 2

Answer:

• H2=B2+P2.
• H2=(10)2+(24)2
• H2=100+576
• H2=676
• H=√676
• H=26 ans