A man goes 240m west and then 100m to south. how far is he from the starting point
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Let OA be the distance covered due west=240m
Let AB be the distance covered due south=100m
In right ΔOAB by Pythagoras theorem we have
OB²=AB²+OA²
OB²=(100)²+(240)²
OB²=10000+57600
OB²=67600
OB=260m
Hence the distance between his starting and final point is 260m
Let AB be the distance covered due south=100m
In right ΔOAB by Pythagoras theorem we have
OB²=AB²+OA²
OB²=(100)²+(240)²
OB²=10000+57600
OB²=67600
OB=260m
Hence the distance between his starting and final point is 260m
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