Question

A man goes 24m due east and then 10m due north north. How far is he away from his initial point

Answer 1

Hey
Here's your answer!!

A man goes 24m due east and then 10m due north north.


|
|
| ( 10 m north)
|
|
-------------------------
( 24 m east)

therfore displacement from his initial point is (24^2 + 10^2)^1/2
= (100 + 576)^1/2
= 676 ^ 1/2
= 26 m. ( ANSWER )

Hope it helps!!

Answer 2

Hey

Here's your answer!!

A man goes 24m due east and then 10m due north north.

|

|

| ( 10 m north)

|

|

-------------------------

( 24 m east)

therfore displacement from his initial point is (24^2 + 10^2)^1/2

= (100 + 576)^1/2

= 676 ^ 1/2

= 26 m. ( ANSWER )

Hope it helps!!