A man goes 3 km North and then 4 km East. Find how far away is he from his initial position ?
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Answered by
17
By Pythagoras theorem,
3²+4² =distance²
9+16=distance²
25=distance²
√25=distance
5 km =distance
I hope this will help you
-by ABHAY
3²+4² =distance²
9+16=distance²
25=distance²
√25=distance
5 km =distance
I hope this will help you
-by ABHAY
Answered by
5
Heya!!
Here is your solution:-
To Find-OB
In ∆OAB
OB² = OA²+AB²
=3²+4²
=9+16=√25=5
THEREFORE,He is 5 km far from his intial position.
Mark as Brainliest answer.
Here is your solution:-
To Find-OB
In ∆OAB
OB² = OA²+AB²
=3²+4²
=9+16=√25=5
THEREFORE,He is 5 km far from his intial position.
Mark as Brainliest answer.
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