a man goes 30 kilometre due north and then 40 km due east
how far away is he from his initial position
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Pythogors therom
Hypotenuse² =base²+perpendicular ²
H²=30²+40²
H²=900+1600
H²=2500
H=√2500
H=50
Therefore 50 km is the distance from his final position to the intial position
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